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rewona [7]
3 years ago
14

Which is greater 16/12 or 9/3

Mathematics
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

\frac{16}{12}  \:  \:   <  \frac{9}{3}

<u>9</u><u>/</u><u>3</u><u> </u><u>is greater</u>

Step-by-step explanation:

\frac{16}{12}  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \frac{9}{3}  \\  \frac{16}{12}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \frac{9 \times 4}{3 \times 4}  \\  \frac{16}{12}  \:  \:  \:  \: \:  \:  \:  \:  \:  \:    \frac{36}{12}  \\  \frac{16}{12}  \:  <  \:  \frac{36}{12}  \\  \\ so \\  \frac{16}{12}  <  \frac{9}{3}

FinnZ [79.3K]3 years ago
5 0

Answer:

the answer is attached to the picture

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You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
aliya0001 [1]

Answer:

q = -6p + 104

Step-by-step explanation:

Linear function:

A linear function has the following format:

q = mp + b

In which m is the slope and b is the q-intercept.

One week you charged $4 per guest and averaged 80 guests per night. The next week you charged $10 per guest and averaged 44 guests per night.

This means that we have these following points: (4,80), (10,44).

Finding the slope:

With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

Change in p: 10 - 4 = 6

Slope: m = \frac{-36}{6} = -6

So

q = -6p + b

Finding b:

We replace one of the points. Replacing (4,80).

q = -6p + b

80 = -6*4 + b

b = 104

So

q = -6p + 104

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3 years ago
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krok68 [10]

Answer:

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Step-by-step explanation:

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3 years ago
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Serjik [45]

Answer:

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Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
Please help me with a) and b) I’m very lost, please explain and how you got your answer
Karo-lina-s [1.5K]

To solve A, complete the square for both variables.

The center is (6,4)

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