Find the surface area of this triangular prism. 3 cm 5 cm 11 cm 4 cm

Oil consumption in China grew exponentially from 8.938 million barrels per day in 2010 to 10.480 million barrels per day in 2013

Afina-wow [57]

Let the year represents x axis and consumption represents y axis.

Since 2010 is the initial year, x=0

and 2013 is third year , so x=3

Co-ordinates are (0,8.938)(3,10.480)

Exponential formula is $y=ab^{x}$

Putting the value of x in the above formula from 1st coordinate,

$8.938=ab^{0}$

As $b^{0}$ = 1

this gives a= 8.938

Now using the 2nd coordinate

$10.480=ab^{3}$

putting the value of a in it we have

$10.480=8.938b^{3}$

taking cube roots on both sides we get

b= 1.05448

Now putting the values of a and b in the exponential formula-

$y=8.938(1.05448)^{x}$

In the year 2028, x=28

so,

$y=8.938(1.05448)^{28}$

y= 39.474

Hence oil consumption per day in 2028 will be 39.474 million barrels.

5 0

2 years ago

Read 2 more answers

Elementary Algebra Skill

mr_godi [17]

The answer is a = $\frac{4}{-3}$

Step-by-step explanation:

1. Convert the mixed fraction to an improper fraction

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2 $\frac{2}{3}$ will be $\frac{8}{3}$

2. Now the equation is,

$\frac{3}{2}$ a - $\frac{4}{3}$ a = $\frac{10}{3}$ + $\frac{8}{3}$ a

3. Take LCM on both sides.

For the left side, multiply the first fraction by $\frac{3}{3}$ and multiply the second fraction by $\frac{2}{2}$

$\frac{3*3}{2*3}$ a - $\frac{4*3}{3*3}$ a = $\frac{10+8a}{3}$

4. Solve by making a the subject

$\frac{9a-8a}{6}$ = $\frac{10+8a}{3}$

$\frac{a}{6}$ = $\frac{10+8a}{3}$

$\frac{3a}{6}$ =10+8a

$\frac{a}{2}$ = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = $\frac{20}{-15}$

a = $\frac{4}{-3}$

Therefore, the answer is a = $\frac{4}{-3}$

Keyword: Equations

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4 0

3 years ago

A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob

Musya8 [376]

Let p be the population proportion. 
We have p=0.60, n=200 and we are asked to find P(^p<0.58). 
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58.