I need the equation to be able to help
Just pretend it’s a 3d right angle triangle and find the length of the hypotenuse.
d = sqrt(6^2 + 10^2 + 15^2) = 19
In the function, the thing that is represented is the area of the walkway along the length of the flower patch.
<h3>How to illustrate the function?</h3>
From the information given, Sam created function A to represent the total area taken up by the flower patch and walkway by multiplying the functions modeling the new total length and width.
Therefore, the thing that is represented is the area of the walkway along the length of the flower patch.
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The intersection of the two red rays forms a set of vertical angle pairs. In such a pair, angles opposite one another have the same measure, so the angle opposite the one labeled 93 degrees also has measure 93 degrees.
The red ray on the right together with the black ray pointing directly to the right form a pair of supplementary angles, whose measures add up to 180 degrees. This means the angle adjacent to the one labeled 128 degrees has measure 180 - 128 degrees.
In any triangle, the interior angles' measures add up to 180 degrees. So we have
? + 93 + (180 - 128) = 180
? + 93 - 128 = 0
? = 128 - 93
? = 35
Answer:
147,000N
Step-by-step explanation:
A1= 2m^2
A2= 0.2m^2
F2= 14,700N
Required
F1, the applied force
Applying the formula
F1/A1= F2/A2
substute
F1/2=14700/0.2
2*14700= F1*0.2
29400= F1*0.2
F1= 29400/0.2
F1=147,000N
Hence, the applied force is 147,000N
