Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
I think the answer is 360
Add 3 standard deviations above and below the mean to get the range in which 99.7% of the data in a normal distribution will fall
6.5 + 4.5 = 11
6.5 - 4.5 = 2
So 2 to 11 ounces would be the interval
Answer:
9 4/33.
Step-by-step explanation:
0.12 repeating = 12/99
= 4/33.
