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Strike441 [17]
3 years ago
7

Please solve for h: V=πr²h

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
Solve for h:V = π h r^2
V = h π r^2 is equivalent to h π r^2 = V:π h r^2 = V
Divide both sides by π r^2:
Answer: h = V/(π r^2)
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How to find slope intercept form when slope equals 3 over 4 passing through 8, 2
IgorC [24]

Answer:

The slope intercept form would be y = 3/4x - 4

Step-by-step explanation:

To find the slope intercept form of this line, we start with using our given information in point-slope form. Then we solve for y.

y - y1 = m(x - x1)

y - 2 = 3/4(x - 8)

y - 2 = 3/4x - 6

y = 3/4x - 4

8 0
3 years ago
What is the outlier in the following set? 29, 2, 28, 30, 26, 31
jok3333 [9.3K]

Answer:

2

Step-by-step explanation:

The outliers is 2 because most of the numbers are around 20-31 range, while 2 is to the far left.

Hope this helped

:)

4 0
3 years ago
Read 2 more answers
3/4 = c/36<br><br><br> I need help with this fraction proble.
Nataliya [291]

Answer:

c = 27

Step-by-step explanation:

given \frac{3}{4} = \frac{c}{36} ( cross- multiply )

4c = 3 × 36 = 108 ( divide both sides by 4 )

c = 27

note that \frac{27}{36} = \frac{3}{4} in simplest form


7 0
4 years ago
4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.
REY [17]

Answer: Is true sometimes.

Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B =  \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]

Here, we would have that:

AB =  \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]

BA =  \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]

You can see that AB and BA are different, then the statement is not always true.

But it is true sometimes, if A or B are the identiti, then I*A = A*I, in this case would be true.

It is also true if A and B are diagonal matrices, let's prove it:

A =  \left[\begin{array}{ccc}a&0\\0&b\end{array}\right] , B =  \left[\begin{array}{ccc}c&0\\0&d\end{array}\right]

AB =  \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA

5 0
4 years ago
The table shows the price for buying bouquets of flowers at a farmer’s market. What is the unit rate? $ per bouquet
valentinak56 [21]

you just need to divided 3 by 9 and it will be 3 or you can divide 6 by 18 and it will be the same so the unite rate is $3

7 0
4 years ago
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