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7nadin3 [17]
2 years ago
10

HELP PLEASE YOU'LL GET BRAINLIEST :)

Mathematics
1 answer:
inna [77]2 years ago
8 0

Step-by-step explanation:

you would divide 489 by 10 and then times that number by 15 and the  divide 20 and get your answer that way

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Beth has a bag of apples.She gives 6 apples to Natasha.Now she has 7 left.How many apples were in the bag at first?
vlabodo [156]
15 from calculations
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3 years ago
16−2t= 3/2t+9<br> need help asap this is my grade plz <br> kahn academy<br> plz help meee
uranmaximum [27]

Answer:

t=2

Step-by-step explanation:

I worked it out and got this answer as well but checked it in a calculator and couldn't send my pic in. I hope its right but if t is with 2 on the denominator then its a whole different answer.

3 0
3 years ago
Does anyone know this?
Bumek [7]

Answer:

B

Step-by-step explanation:

Initial mean = 156, Changed mean = 163.92

So, mean increases. Only condition that satisfies this is B.

7 0
3 years ago
Write the expression-3x2+2y2+5xy-2y+5x2-3y2 in simplest form A how many terms are in the simplified expression? B how many terms
natima [27]

Answer:

  • 4
  • 2

Step-by-step explanation:

  = x²(-3 +5) +y²(2 -3) +5xy -2y

  = 2x² -y² +5xy -2y

a) there are 4 terms in the simplified expression

b) 2 terms have negative coefficients (-y² and -2y)

5 0
3 years ago
Find the perimeter of triangle ABC with vertices A(6, 3), B(6, - 2) , and C(- 4, 3) .
anyanavicka [17]

Answer:

26.2 units

Step-by-step explanation:

We are given the points/vertices

A(6, 3),

B(6, - 2) , and

C(- 4, 3)

Step two

Let us find the distances between the given points/vertices

A-B =A(6, 3) to B(6,-2)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6-6)²+(-2-3)²)

d=√(-2-3)²)

d=√(-5)²)

d=5 units

B-C=B(6, - 2) to C(-4, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((-4-6)²+(3+2)²)

d=√(-10)²+(5)²)

d=√100+25

d=√125

d=11.2 units

C-A=C(-4, 3) to A(6, 3)

d=√((x2-x1)²+(y2-y1)²)

Substitute

d=√((6+4)²+(3-3)²)

d=√(10)²

d=√100

d=10 units

Hence the perimeter is 5+11.2+10

P=26.2 units

4 0
3 years ago
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