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MrRa [10]
3 years ago
13

Which expression is the factored equivalent of x2 - 5x + 4?

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

Step-by-step explanation:

A

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(7x+2)(20-3x/4) = 140x + 40 - 21x²/4 - 3x/2 = -21/4 x² + 138 1/2 x + 40

this is one of those multiplications that doesn't make the result look any simpler...
3 0
2 years ago
Sandra rode her bike 5 times as many miles as Barbara. If b, the distance Barbara rode, equals 3.4 miles, what is the correct ex
Debora [2.8K]

The expression s = 5b represents the Sandra rode her bike and the distance Sandra rode, equals 17 miles.

<h3>What is distance?</h3>

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

We have:

Sandra rode her bike 5 times as many miles as Barbara. If b, the distance Barbara rode, equals 3.4 miles.

b = 3.4 miles

Let's suppose the s is the distance Sandra rode then,

s = 5b

The above expression represents the Sandra rode her bike.

Plug b = 3.4 miles

s = 5(3.4) = 17 miles

Thus, the expression s = 5b represents the Sandra rode her bike and the distance Sandra rode, equals 17 miles.

Learn more about the distance here:

brainly.com/question/26711747

#SPJ1

3 0
2 years ago
Le regioni italiane bagnate dal mare sono un insieme?
arsen [322]

Answer:

non so cosa intendi per intero

Step-by-step explanation:

Può essere più preciso?

7 0
2 years ago
S||P FIND VALUE OF Z !
NNADVOKAT [17]

Answer:

Step-by-step explanation:

Please excuse my handwriting lol.

7 0
3 years ago
Given that vector p=i+2j-2k and q=2i-j+2k, find two vectors m and m satisfying the condition;
Stels [109]

9514 1404 393

Answer:

  • m = j +k
  • n = 2i +k

Step-by-step explanation:

There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

Let m = 0i +1j +ak. Then we require ...

  m·p = 0 = 0×1 +1×2 +a(-2)   ⇒   0 = 2 -2a   ⇒   a = 1

m = 0i +1j +1k

__

Let n = 2i +0j +bk

  n·p = 0 = 2×1 +0×2 +b(-2)   ⇒   2 -2b = 0   ⇒   b = 1

n = 2i +0j +1k

6 0
2 years ago
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