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nadezda [96]
3 years ago
15

How do u rename on the hour? What does on the hour mean?? Plz help guys I really would appreciate it I will give u 43 points if

u answer

Mathematics
2 answers:
Alecsey [184]3 years ago
6 0
For example, if someone says "5, on the hour", it means at 5:00
nlexa [21]3 years ago
4 0
On the hour means that it's exactly an hour. An example would be 5:00 on the hour. Therefore, it would be exactly 5:00. Not 5:01 or 4:59. 

You can rephrase this by saying:
"On the Dot"
"Exactly __ o clock"
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What is the Inverse Equation<br><br>f(x) =6x-1 ?? please I need help!​
Scrat [10]

Answer:

f^{-1}(x)=\frac{x+1}{6}

Step-by-step explanation:

So we have the function:

f(x)=6x-1

To find the inverse function, switch x and f(x), change f(x) to f⁻¹(x), and solve for f⁻¹(x). Therefore:

f(x)=6x-1

Switch:

x=6f^{-1}(x)-1

Add 1 to both sides:

x+1=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{x+1}{6}

And that's our answer :)

5 0
3 years ago
Find the x intercepet
Pepsi [2]

Answer:

7.5

Step-by-step explanation:


5 0
3 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
Suppose you own two stocks, A and B. In year 1, stock A earns a 2% return and stock B earns a 9% return. In year 2, stock A earn
Verizon [17]

Answer:

Both the stock have the same expected return.

Step-by-step explanation:

In year 1 the return earned by stocks A and B are:

Stock A = 2% return

Stock B = 9% return

In year 2 the return earned by stocks A and B are:

Stock A = 18% return

Stock B = 11% return

Compute the expected return for stock A as follows:

Expected\ return\ for\ A=\frac{2+18}{2}=10\%

Compute the expected return for stock B as follows:

Expected\ return\ for\ B=\frac{9+11}{2}=10\%

Thus, both the stock have the same expected return.

7 0
3 years ago
1. How do you determine the constant that you should add to an expression in the form x^2+bx so that it becomes a perfect square
Arada [10]

now heres a step by step explanation Step-by-step explanation: your welcome

5 0
3 years ago
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