Answer:
∠NMJ and ∠KJH
Step-by-step explanation:
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
Answer:
x = 3/4
Step-by-step explanation:
Step 1: Write equation
5x - 2(x + 1) = 1/4
Step 2: Solve for <em>x</em>
- <u>Distribute -2:</u> 5x - 2x - 2 = 1/4
- <u>Combine like terms:</u> 3x - 2 = 1/4
- <u>Add 2 to both sides:</u> 3x = 9/4
- <u>Divide both sides by 3:</u> x = 3/4
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
5(3/4) - 2(3/4 + 1) = 1/4
15/4 - 2(7/4) = 1/4
15/4 - 14/4 = 1/4
1/4 = 1/4
Answer:
median
Step by step:
the line segment from a vertex to the midpoint of the opposite side. It is also an angle bisector when the vertex is an angle in an equilateral triangle or the non-congruent angle of an isoceles triangle.
we have
The solution is the shaded area above the dotted line
therefore
The answer in the attached figure
