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Maksim231197 [3]
3 years ago
8

In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both

courses. How many students are not enrolled in either course?
a. 6
b. 15
c. 24
d. 33
e. 54
Mathematics
2 answers:
galina1969 [7]3 years ago
7 0
78-41-22+9=24 the students are mutually exclusive. The answer is C
Nezavi [6.7K]3 years ago
7 0
The answer is A (6) because 41+22+9=72, and there are 72 students enrolled in either of the courses. When you subtract 72 from 78 you get 6, which is the ending amount of students  hat are not enrolled in French class, or German class.
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Please help.<br> Is algebra.
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Answers:

  • Blank 1:  4
  • Blank 2:  -1

So the solution is (x,y) = (4, -1)

=============================================================

Work Shown:

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6x + 7( y ) = 17

6x + 7( -3x+11 ) = 17 ... replace every copy of y with -3x+11

6x - 21x + 77 = 17

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We'll use this x value to find y

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------------------------

To check the solution, we plug x = 4 and y = -1 into each equation

Plugging the values into the first equation leads to...

y = -3x+11

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This is effectively already done in the last part of the previous section. But it doesn't hurt to verify like this regardless.

We'll need to verify the second equation as well.

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3 years ago
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7 0
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20 POINTS AND BRAINLIEST!
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Answer:

<A =21

<B = 84

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Step-by-step explanation:

<A =x

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Combine like terms

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Add 30 to each side

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Divide by 10

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Substituting x into the equations for angles A, B and C

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