Question

The perimeter of the triangle is 42. Find the length of all the sides.

Answer 1

Given :-

• Perimeter of triangle = 42

• Side 1 of triangle = (x + 4)

• Side 2 of triangle = (3x + 8)

• Side 3 of triangle = (5x + 6)

To find:-

• Length of sides

Explanation:

So to find length of sides we have to find the value of x.We can find value of x , by this formula:

$\bigstar \boxed{ \rm perimeter \: of \triangle \: = side_1 + side_2 + side_3}$

So:-

$\dashrightarrow \tt perimeter \: of \triangle \: = side_1 + side_2 + side_3$

$\dashrightarrow \tt 42 = (x + 4) + (3x + 8)+( 5x + 6)$

$\dashrightarrow \tt 42 = x + 4+ 3x + 8+5x + 6$

$\dashrightarrow \tt 42 = x + 3x+5x+ 4 + 8 + 6$

$\dashrightarrow \tt 42 = 9x+ 4 + 8 + 6$

$\dashrightarrow \tt 42 = 9x+ 18$

$\dashrightarrow \tt 42 - 18 = 9x$

$\dashrightarrow \tt 24 = 9x$

$\dashrightarrow \tt 9x = 24$

$\dashrightarrow \tt x = \dfrac{24}{9}$

$\dashrightarrow \bf x =2.67 \{approx \}$

• Side 1 of triangle = (x + 4)
• Side 1 of triangle =2.67 + 4
• Side 1 of triangle = 6.67

• Side 2 of triangle = 3x + 8
• Side 2 of triangle = 3 × 6.67 + 8
• Side 2 of triangle = 20.01 + 8
• Side 2 of triangle = 28.01

• Side 3 of triangle = 5x + 6
• Side 3 of triangle = 5 × 2.67 + 6
• Side 3 of triangle = 13.35 + 6
• Side 3 of triangle = 19.35

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~WindyMint