Is there answer choices because I’m not understanding what you want me to answer
Explanation:
A default constructor is a constructor that present in the class by default with no parameters when we write a new constructor with parameters it is called overloaded constructor.There can be different overloaded constructors in the same class.
The main difference between default constructor and overloaded constructor is that the default constructor does't have any parameters while the overloaded constructors have parameters.
A multinational corporation, or MNC, is a company which produces goods and services and has offices in several other countries while a global corporation or company is a company which also has trade relations with several other countries. ... MNCs have official headquarters while global companies do not.
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
Answer:
bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}
for bear in bears:
if bears[bear] == "friendly":
print("Hello, "+bear+" bear!")
else:
print("odd")
Explanation:
A dictionary called bears is given. A dictionary consists of key-value pairs.
You need to check each key-value pairs in bears and find the ones that have "friendly" as value using a for loop and if-else structure. In order to access the values of the dictionary, use the dictionary name and the key (inside the loop, the key is represented as bear variable). If a key has a value of "friendly", print the greeting. Otherwise, print "odd".
