I’m guessing that what’s being looked at here moreso is the space complexity of these algorithms. Heap sort and insertion sort I believe have the lowest of these, but insertion sort is also known to not be the best with time complexity. Therefore heap sort should take the cake
If the network administrator found that one of his routers is slow in performance better to check the traffic packet transactions. If any huge file size is been transferred better to disconnect the router and reconnect.
Possible to kill the network task packet so the network speed can be restored.
<u>Explanation:</u>
Moreover, possible to scan the end-user PC or workstation or desktop whether any malware or spyware is affected, if so better to remove that particular PC or workstation or desktop to disconnected from the router.
Updating the PC or workstation or desktop OS patches to be done at regular intervals.
decibels i believe is the correct answer. hope it helps :)
Answer:
import java.util.Scanner;
class Main {
public static int calcSeries(int n) {
int sum = 0;
for(int i=10; i>=n; i--) {
sum += i;
}
return sum;
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = 0;
do {
System.out.print("Enter n: ");
n = reader.nextInt();
if (n >= 10) {
System.out.println("Please enter a value lower than 10.");
}
} while (n >= 10);
reader.close();
System.out.printf("sum: %d\n", calcSeries(n));
}
}
