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pashok25 [27]
3 years ago
10

Lets find the mean ofthe data (2,1,2,4,5,4 together)

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

mean is 3.

mode is 2, 4

median is 3

Step-by-step explanation:

pls mark brainliest

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The question is in the picture above
weqwewe [10]
X= # of regular bouquets
y= # of mini bouquets

5x+3y=118

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1. Solve for Y 1/2y+4x=z
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I hope this helps you

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Does (2,1 ) make the equation true? 2x+7y>=10
madreJ [45]

Answer:

2x+7y>=10

Replace x and y with 2 and 1

2*2+7*1>=10

2*2=4

7*1=7

4+7>=10

7+4=11

2x+7y>=10 is a true statement

Because 11 is greater than 10 and it doesnt have to be equal to 10 as long as its greater.

3 0
3 years ago
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justine answered 68 questions correctly on an 80 question test. express this amount as a fraction. percent, and decimal.
BartSMP [9]
This is actually a simple division problem. First, let as express this as a fraction. So in order to express it as 68 out of 80, we just have to write the fraction as 68/80. If we would express this in simplest form, then it will 17/20. After that, we will have express it as a decimal. To do this, we just have to divide it in order to get the decimal form. So if we do this, we will get an answer of 0.85. Now in order to turn it into a percentage, we have to multiply it by 100 and you will get 85%
7 0
3 years ago
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The ramp in the picture makes an angle of 73° with the doorpost. What is the measure of the angle ∠QPR, between the ramp and the
siniylev [52]

Answer:

A.  ∠ QPR = 17°

Step-by-step explanation:

From the given information, let QP be the length of the ramp.

Then, ∠ QPR is the angle between the ramp and the ground.

∠ PQR is the angle between the ramp and the doorpost and

∠ QRP is the angle between the doorpost and the ground.

Clearly, ∠ PQR = 73° (given)

∠ QRP = 90° (since doorpost and the ground are perpendicular to each other)

Now, use triangle sum propoerty of ΔQPR, we get,

∠ QPR + ∠ PQR + ∠ QRP = 180°

∠ QPR + 73 + 90 = 180°

∠ QPR + 163 = 180°

∠ QPR = 180 - 163

∠ QPR = 17°




6 0
4 years ago
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