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3 years ago

justine answered 68 questions correctly on an 80 question test. express this amount as a fraction. percent, and decimal.

2 answers:

7 0

This is actually a simple division problem. First, let as express this as a fraction. So in order to express it as 68 out of 80, we just have to write the fraction as 68/80. If we would express this in simplest form, then it will 17/20. After that, we will have express it as a decimal. To do this, we just have to divide it in order to get the decimal form. So if we do this, we will get an answer of 0.85. Now in order to turn it into a percentage, we have to multiply it by 100 and you will get 85%

Tomtit [17]3 years ago

6 0

$\frac{68}{80} = \frac{17\times 4}{20\times 4} = \boxed{\bf{\frac{17}{20} }}\\\\\frac{17}{20} = \boxed{\bf{0.85}}$

0.85 × 100 = 85%

68 questions answered correctly out of 80 can be expressed as:

a fraction: 17/20
a decimal: 0.85
a percent: 85%

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Which of these are statistical questions that you could ask to gather data on the types of transportation to school?

Pavlova-9 [17]

Answer:

A statistical question is a question that can be answered by collecting data that vary. For example, “How old am I?” is not a statistical question, but “How old are the students in my school?” is a statistical question.

The closest ones are - B and E

7 0

3 years ago

The point P(8, 6) is on the terminal side of θ. Evaluate sin θ.

vladimir2022 [97]

Ok so let me help you with this. Here is the procedure:
r² = x² + y² = 8² + 6² = 100
r = 10
x = r cosθ
y = r sinθ
sinθ = y/r = 6/10 = 3/5
Hope this is what you are looking for

3 0

4 years ago

Read 2 more answers

Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minut

solmaris [256]

Answer:

6.11km/hr

Step-by-step explanation:

Let the speed that Kelli swims be represented by Y

Speed of the river = 5km/hr

Distance = Speed × Time

Kelli swam upstream for some distance in one hour

Swimming upstream takes a negative sign, hence:

1 hour ×( Y - 5) = Distance

Distance = Y - 5

She then swam downstream the same river for the same distance in only 6 minutes

Downstream takes a positive sign

Converting 6 minutes to hour =

60 minutes = 1 hour

6 minutes =

Cross Multiply

6/60 = 1/10 hour

Hence, Distance =

1/10 × (Y + 5)

= Y/10 + 1/2

Equating both equations we have:

Y - 5 = Y/10 + 1/2

Collect like terms

Y - Y/10 = 5 + 1/2

9Y/10 = 5 1/2

9Y/ 10 = 11/2

Cross Multiply

9Y × 2 = 10 × 11

18Y = 110

Y = 110/18

Y = 6.1111111111 km/hr

Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.

4 0

3 years ago

What fraction of 56 of 21?

Paraphin [41]

Seventeen over seven

8 0

3 years ago

Read 2 more answers

GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m

Harrizon [31]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

Let $\mu$ = average mg of mercury in compact fluorescent bulbs.

So, Null Hypothesis, $H_0$ : $\mu \leq$ 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, $H_A$ : $\mu$ > 3.50 mg {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean mg of mercury = 3.59

$\sigma$ = population standard deviation = 0.18 mg

n = sample of bulbs = 25

So, test statistics = $\frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }$

= 2.50

The value of z test statistics is 2.50.

Now, P-value of the test statistics is given by;

P-value = P(Z > 2.50) = 1 - P(Z $\leq$ 2.50)

= 1 - 0.9938 = 0.0062

Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0

3 years ago