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sergeinik [125]
3 years ago
15

Need help with my math checking it over just making sure its right please help it is a lot!

Mathematics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

14. 14.86 (simple subtraction)

15. 4 dollars (156/39 = 4)

18. 49 (36,39,44,48,50,50,54,55 so mean of 48 and 50 is 49)

19.14 (3.5/0.25)

20. A(understanding question contex)

25. 3a + 3b or C (add all the a's and b's together)

26. 5 (Divide apples by 3)

28.C(multiply all the sides together)

29. A (12/7 is fraction form of 12 : 7)

30. C (rate is 20 so 6 * 20 = 120)

31. D

Hoped this helped, this took a while to do :)

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Is this graph proportional or non-proportional?
grigory [225]

Answer:

Yes

Step-by-step explanation:

The slope intercept form is y=1.38x

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3 years ago
What is the answer to -5 ( 4w +12) =15 make sure you write the answer as a decimal
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Answer:

w= -3.75

Step-by-step explanation:

-5(4w+12) =15

-20w -60=15

-20w=75

w=-3.75

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How many solutions does this graph have​
amm1812

Answer:

no solutions

Step-by-step explanation:

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2 years ago
Rewrite each expression as a polynomial in standard form: (2x^2 − x^3 − 9x +1) − (x^3 +7x − 3x^2 +1)
Vitek1552 [10]

Answer:

Polynomial in standard form will be -2x^3+5x^2-16x

Step-by-step explanation:

We have given polynomial 2x^2-x^3-9x+1-(x^3+7x-3x^2+1)

We have to write this polynomial in standard form

For writing in standard form we have to first subtract the polynomial and then rearrange the order

So 2x^2-x^3-9x+1-(x^3+7x-3x^2+1)=2x^2-x^3-9x+1-x^3-7x+3x^2-1=-2x^3+5x^2-16x

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8 0
2 years ago
Using the letters in the word INNOVATIVE, find the number of permutations that can be formed using 4 letters at a time. Show you
lyudmila [28]

Answer:  1) 5040 and 2) 165

Step-by-step explanation:

1) Here total number of letters = 10

The number of permutations that can be formed using 4 letters at a time

= P (10, 4)

= 10_P_4

= \frac{10!}{(10-4)!}

=  \frac{10!}{6!}

= \frac{10\times 9\times 8\times 7\times 6!}{6!}

= 10 × 9 × 8 × 7

= 5040

2) Here the total number of machine = 11

The different combinations of machines can Geoff choose from to use

= 11_C_3

= \frac{11!}{(11-3)!3!}

= \frac{11!}{8!3!}

= \frac{11\times 10\times 9\times 8!}{8!\times 6}

= 11 × 5 × 3

= 165

5 0
3 years ago
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