Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) = 
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
Answer:
Step-by-step explanation:
The question is not terrifically worded. What it means is "What is the y value when x = 8" That's what f(8) conveys to you.
The answer (though zero is not marked and should be) is 1 unit above 0.
The answer is f(8) = 1 He's heading back.
Answer:
The answer is c) y= 1.8(2.5)^x
Step-by-step explanation:
I just took the test.
Turn both mixed fractions into improper fractions
2 3/5 = 13/5
1 4/7 = 11/7
now multiply the improper fractions
13/5 x 11/7
143/35 or 4 3/35
Total change in relation to when Greg first started decreasing his run time : -6 minutes (at the end of 6 weeks)
Expression : -x (x is the number of weeks)