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Rama09 [41]
3 years ago
9

What is a common factor for the two fractional terms StartFraction 5 over 8 EndFraction x andStartFraction 11 over 8 EndFraction

x y? The terms can be written as 5StartFraction 1 over 8 EndFraction(x) and 11StartFraction 1 over 8 EndFractionxy. 5 StartFraction 1 over 8 EndFraction x StartFraction 5 over 8 EndFraction y
Mathematics
2 answers:
inessss [21]3 years ago
9 0

Answer:

B. 1/8x

Step-by-step explanation:

Dafna1 [17]3 years ago
4 0

Answer:

\frac{1}{8x}

Step-by-step explanation:

Given two fractional terms \frac{5}{8x}\ and\ \frac{11}{8xy}. Their common factor is a value or function that can go in both fractional terms. The terms can be written as shown.

\frac{5}{8x} = 5 *\frac{1}{8x}

\frac{11}{8xy} = 11 * \frac{1}{8x} * \frac{1}{y}

It can be seen from the both equations that they both have \frac{1}{8x} as one of their factors i.e <em>1/8x is common to both fractional terms</em>. This gives the common factor for the two fractional terms as \frac{1}{8x}

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A cylinder of manganese (length 4.00 cm, diameter = 1.00 cm) has a mass of 22.62 g. What is the density of manganese?
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Equation for density is mass/volume

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3 years ago
How many ways can 6 people be chosen and arranged in straight line if there are 8 people to choose from? a. 48.b. 720.c. 20, 160
Ipatiy [6.2K]

Answer:

<h2>C. <em>20,160</em></h2>

Step-by-step explanation:

This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.

nPr = n!/(n-r)!

Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.

8P6 = 8!/(8-6)!

8P6 = 8!/2!

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3 years ago
An artist needs to purchase jars of paint. The table shows Which quantity container is the better buy?
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Answer:8-oz jar

First, we have to find out what is the unit rate of the 2-oz jar. $1.50÷2 is $.75.

Second, we have to find the unit rate of the 4-oz jar. $2.92÷4=$73.

Third, we have to find the unit rate of the 8-oz jar. $5.68=$.71.

Fourth, we have to find the unit rate of the 16-oz jar. The division for this one may be tricky. From dividing $11.62 by 16, is stopped at the 3rd number I got from dividing. I got $.726. This is not a value of cents and the value can't go in the thousandths place. So, I rounded .726. I got $.73. So $11.62÷16=$.73.

Lastly, you have to compare the amounts.

The lowest amount or better buy, is $.71 or 8-oz jar.

8 0
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