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2 years ago

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2

Mathematics

1 answer:

saw5 [17]2 years ago

5 0

Answer:

r = 3 1/4

Step-by-step explanation:

Here, we want to find the value of r given the values

Firstly, we will write r as the subject of the formula

U = π ( r + h)

U/π = r + h

r = U/π - h

Now substitute;

U = 16 1/2 = 33/2

h = 2

π= 22/7

r = 33/2/22/7 - 2

r = (33/2 * 7/22) - 2

r = 21/4 - 2

r = (21-8)/4

r = 13/4 = 3 1/4

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Y -13 --------- = y -7

mario62 [17]

y-13 / y-7

cross multiply

y-13 = y-7

collect like terms

y+y =-7+13

2y= 13 -7

2y = 6

divide both sides by 2

2y/ 2y = 6/2

y= 3

I hope this helped

4 0

3 years ago

I don't know if this is answerable over text-..

andrew11 [14]

Step-by-step explanation:

i wish I could help but no idea

8 0

2 years ago

3x+4y=-3 x+2y=-1 how to solve this problem

erma4kov [3.2K]

Answer:

x,y= -1,0

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Solve for x: 2x - 2 > 4x + 6

laiz [17]

Isolate the x. Subtract 4x from both sides, and add 2 to both sides

2x (-4x) - 2 (+2) > 4x (-4x) + 6 (+2)

2x - 4x > 6 + 2

Simplify. Combine like terms

-2x > 8

Isolate the x. Divide -2 from both sides. Note that you are dividing a negative number. When doing so, flip the sign.

-2x/-2 > 8/-2

x > 8/-2

x < -4

x < -4, or (1) is your answer

hope this helps

7 0

3 years ago

Please help me if you can! Thank you (:

AnnyKZ [126]

Answer:

The value of f(2) would be -40.

Step-by-step explanation:

Given function is,

$f(x) = 2x^3 - 3x^2 - 18x - 8$

Substituting x = 2 in the above function,

We get,

$f(2) = 2(2)^3 - 3(2)^2 - 18(2) - 8$

$=2(8) - 3(4) - 36 - 8$

$=16 - 12 - 44$

$\implies f(2)= -40$

Hence, the value of f(2) would be -40.

4 0

3 years ago

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2​

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2