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3 years ago

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2

Mathematics

1 answer:

saw5 [17]3 years ago

5 0

Answer:

r = 3 1/4

Step-by-step explanation:

Here, we want to find the value of r given the values

Firstly, we will write r as the subject of the formula

U = π ( r + h)

U/π = r + h

r = U/π - h

Now substitute;

U = 16 1/2 = 33/2

h = 2

π= 22/7

r = 33/2/22/7 - 2

r = (33/2 * 7/22) - 2

r = 21/4 - 2

r = (21-8)/4

r = 13/4 = 3 1/4

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Answer:

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Step-by-step explanation:

Estimating a root to the nearest tenth can be done a number of ways. The method shown here is to identify the tenths whose squares bracket the value of interest.

You have answered the questions of parts 1 to 3.

You are given that ...

7.2² = 51.84

7.3² = 53.29

This means 53 lies between 7.2² and 7.3², so √53 lies between 7.2 and 7.3.

53 is closer to 7.3², so √53 will be closer to 7.3 than to 7.2.

7.3 is a good estimate of √53 to the tenths place.

_____

<em>Additional comment</em>

For an integer n that is the sum of a perfect square (s²) and a remainder (r), the square root is between ...

s +r/(2s+1) < √n < s +r/(2s)

For n = 53 = 7² +4, this means ...

7 +4/15 < √53 < 7 +4/14

7.267 < √53 < 7.286

Either way, √53 ≈ 7.3.

The root is actually equal to the continued fraction ...

$\sqrt{n}=\sqrt{s^2+r}=s+\cfrac{r}{2s+\cfrac{r}{2s+\dots}}$

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If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2​

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2