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BartSMP [9]
3 years ago
5

If U=π (r+h),find the value of "r" when U=16 whole 1 upon 2 and h=2​

Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

r = 3 1/4

Step-by-step explanation:

Here, we want to find the value of r given the values

Firstly, we will write r as the subject of the formula

U = π ( r + h)

U/π = r + h

r = U/π - h

Now substitute;

U = 16 1/2 = 33/2

h = 2

π= 22/7

r = 33/2/22/7 - 2

r = (33/2 * 7/22) - 2

r = 21/4 - 2

r = (21-8)/4

r = 13/4 = 3 1/4

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Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

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so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

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\mathrm{Apply\:rule}\:\frac{a}{1}=a

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Therefore

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