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Andreas93 [3]
3 years ago
5

Pls help me! And explain how you found the answer pls

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

y = \frac{1}{2} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 22, - 14) and (x₂, y₂ ) = (- 18, - 12)

m = \frac{-12+14}{-18+22} = \frac{2}{4} = \frac{1}{2} , thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 18, - 12) , then

- 12 = - 9 + c ⇒ c = - 12 + 9 = - 3

y = \frac{1}{2} x - 3 ← equation of line

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Using decimals the answer would be

70 x 0.3 = 21

Using fractions the answer would be

70 / 1 x 3/10  =  210/10  =  21 times on base is the estimate
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Find the length of side x to the nearest tenth.<br> 309<br> X<br> 60°
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3 years ago
The sum of 7 times a number and 23 is equal to 79.
AlladinOne [14]
<h2>ANSWER:</h2>

LET THE NUMBER BE "X"

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3 years ago
Read 2 more answers
/////I need help fast/////
gladu [14]
A(4) =13


a(1) = 1
a(2)=5
a(3)=9
a(4)=13
a(5)=17

So, the arithmetic formula is: a(n) = a(n-1) + d

If we look at the formula, the numbers change by +1, which is our d

We can test our formula by look for 2,
a(2)= a(2-1)+4
a(1)+4
1+4

a(2)=5


Even though the sequence tells us, we can test our formula anyhow

a(4)= a(4-1)+4
a(3)+4
9+4

a(4)=13
5 0
4 years ago
A 4 meter tall bear is walking in the woods and sees honey flavoured chips strapped to a flashlight hanging from a tree 7 meters
otez555 [7]

Answer:

The length of the shadow is decreasing 8 metres per second.

Step-by-step explanation:

In the attached figure, we draw the situation of the bear approaching the tree.

We can use the Tales to make some calculations.

The proportion between the height of the bear (h) and his shadow (S) is equal to the proportion between the height of the flashlight (H) and the sum of the distance of the bear (d) and the bear shadow.

This can be written as:

\frac{h}{S} =\frac{H}{S+d}

If we clear S we have:

S*H=S*h+d*h\\\\(H-h)*S=d*h\\\\S=(\frac{h}{H-h}) d

We know that the distance is a function of time and it is reduced, as the bear approaches the tree, as a rate of 6 m/s.

We can express then the rate of variation of the shadow S as:

\Delta S=S_2-S_1=(\frac{h}{H-h}) (d_2-d_1)=(\frac{h}{H-h}) \Delta d\\\\\\\Delta d=-6\\\\H=7\\\\h=4\\\\\\\Delta S=(\frac{4}{7-4}) *(-6)=\frac{4}{3} *(-6)=-8

The length of the shadow is decreasing 8 metres per second.

6 0
3 years ago
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