If A( 6, -1) , B( 1,3) and C( k, 8) are three points such that AB = BC, find the value of k

1 answer:

7 0

Answer:

De value of k is 9

Step-by-step explanation:

6,-1

b(1,3)

(k,8)

am using bodmas

a6-1×1=6a

b1×3=3b

abc=8

6a+3b+8=17-8

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