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yKpoI14uk [10]
3 years ago
7

Solve the system of equations using row operations. Write your answer in the form (x, y).

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

(5, - 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = - 2 → (1)

3x - y = 19 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the y- term

9x - 3y = 57 → (3)

Add (1) and (3) term by term to eliminate y

(2x + 9x) + (3y - 3y) = (- 2 + 57), that is

11x = 55 ( divide both sides by 5 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

2(5) + 3y = - 2

10 + 3y = - 2 ( subtract 10 from both sides )

3y = - 12 ( divide both sides by 3 )

y = - 4

Solution is (5, - 4 )

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2 5/8 ×3 1/7<br> What's the answer for this ?
nikdorinn [45]

Answer:

8 \frac{1}{4}

Step-by-step explanation:

Let us solve

2 \frac{5}{8}  \times 3 \frac{1}{7}  \\  \frac{21}{8}  \times  \frac{22}{7}  \\  \frac{462}{56}  \\  \frac{462 \div 2}{56 \div 2}  \\  \frac{231}{28}  \\  \frac{231 \div 7}{28 \div 7}  \\  \frac{33}{4}  \\ 8 \frac{1}{4}

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5 0
3 years ago
Read 2 more answers
-2x-9y=-25 -4x-9y=-23 system with elimination
REY [17]
Multiply the first equation by -2. It turns into 4x+18y=50 and the other one stays -4x-9y=-23. Then you "eliminate" the equations by "adding" them. Set it up like this: 
4x+18y=50
      +
-4x-9y=-23
4x-4x= 0. 18y-9y= 9y and 50-23= 27
SO: 9y= 27 and y= 3
And then you plug that in to one equation: 4x +18(3)= 50. 4x= 50-(18*3)
4x= -4, so x=-1.
Plug it back in to check! 
Hope this helps. Happy solving! :)
4 0
3 years ago
Read 2 more answers
14. Suppose that 1 out of every 10,000 doctors in a certain region is infected with the SARS virus; in the same region, 20 out o
hram777 [196]

Answer:

The person in the at-risk population is much more likely to actually have the disease

Step-by-step explanation:

The probability of a randomly selected doctor having the disease is 1 in 1,000 (P(I)=0.0001).

The probability that a doctor is infected with SARS, given that they tested positive is:

P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.0001*0.99}{0.0001*0.99+(1-0.0001)*0.01}\\P(I|+)=9.9*10^{-3}

The probability of a randomly selected person from the at-risk population having the disease is 20 in 100 (P(I)=0.20).

The probability that a person in the at-risk population is infected with SARS, given that they tested positive is:

P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.2*0.99}{0.2*0.99+(1-0.2)*0.01}\\P(I|+)=0.962

Therefore, the person in the at-risk population is much more likely to actually have the disease

3 0
3 years ago
Help plsssssss no links or files
Doss [256]

Answer:

7500 yds^2

Step-by-step explanation:

A = \frac{1}{2}Bh

A = \frac{1}{2} 50 * 300

A = 25 * 300

A = 7500

4 0
3 years ago
What is the solution to (x + 8) &gt; (2x + 10)?
OverLord2011 [107]
The answer to this is x < -2
7 0
3 years ago
Read 2 more answers
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