Question

Def sum_divisors(n): sum =1 # Return the sum of all divisors of n, not including n x=int(n**0.5) for i in range(2,(x//1)+1): if n%i==0: sum=sum+i if n%i==0 and n/i!=i: sum=sum+(n/i) return sum print(sum_divisors(0)) # 0 print(sum_divisors(3)) # Should sum of 1 # 1 print(sum_divisors(36)) # Should sum of 1+2+3+4+6+9+12+18 # 55 print(sum_divisors(102)) # Should be sum of 2+3+6+17+34+51 # 114

Answer 1

Answer:

This is a python program that counts the number of divisors of a given number and calculates the sum of the divisors.

Explanation:

The first line defines a function "sum_divisors" with an argument "n". The square root of the argument is converted to integer and assigned to the variable "x", then a for loop is used to iterate through the range 2 to the calculated nth number of divisors in the argument.The return keyword returns the sum value.

The function is called with several arguments and printed with the print function.