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zlopas [31]
2 years ago
10

PLEASE I NEED HELP WITH THIS, IS FOR TODAY

Computers and Technology
2 answers:
MAVERICK [17]2 years ago
6 0

Answer:

b

Explanation:

faust18 [17]2 years ago
6 0
The answer is b ! gl <3
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write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
2 years ago
Jensen is a senior developer for Hackers R'Us, a company that helps secure management information systems. Jensen's new task is
Harlamova29_29 [7]

Answer:

b. white-hat hacker

Explanation:

A White-hat Hacker, also known as an Ethical Hacker is an information security specialist, known for performing penetration testing and checks in search for information and communications system's vulnerabilities on demand for his/her clients.

These efforts are meant to find security risks before someone else does, who could cause any kind of damage to the systems or unauthorized access to sensitive information

6 0
3 years ago
Mix ‘em Let s1 and s2 be 2 c-strings of the same length. Write a function char* mixem(char*s1, char* s2) which returns a c-strin
Shkiper50 [21]

Answer:

See Explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace std;

char *mixem(char *s1, char *s2);

int main() {

cout << mixem("abc", "123") << endl;

cout << mixem("def", "456") << endl;

return 0;

}

char *mixem(char *s1, char *s2) {

char *result = new char[1 + strlen(s1) + strlen(s2)];

char *p1 = s1;

char *p2 = s2;

char *p = result;

while (*p1 || *p2) {

if (*p1) {

*p = *p1;

p1++;

p++;

}

if (*p2) {

*p = *p2;

p2++;

p++;

}

}

*p = '\0';

return result;

}

5 0
3 years ago
Please help, I can't find the answer but I understand the topic.
gladu [14]

Answer:

x=(2+3)*3;

Explanation:

3 0
3 years ago
Read 2 more answers
Given a string, convert the characters of the string into opposite case,i.e. if a character is lower case than convert it into u
o-na [289]

Answer:

// CPP program to Convert characters  

// of a string to opposite case  

#include<iostream>  

using namespace std;  

// Function to convert characters  

// of a string to opposite case  

void convertOpposite(string &str)  

{  

int ln = str.length();  

 

// Conversion according to ASCII values  

for (int i=0; i<ln; i++)  

{  

 if (str[i]>='a' && str[i]<='z')  

 //Convert lowercase to uppercase  

  str[i] = str[i] - 32;  

 else if(str[i]>='A' && str[i]<='Z')  

 //Convert uppercase to lowercase  

  str[i] = str[i] + 32;  

}  

}  

// Driver function  

int main()  

{  

string str = "GeEkSfOrGeEkS";  

 

// Calling the Function  

convertOpposite(str);  

 

cout << str;  

return 0;  

}  

Explanation:

8 0
3 years ago
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