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vekshin1
2 years ago
9

If 2.6( d +1.4 )- 2.3d= 4,what is d?

Mathematics
1 answer:
Aleks04 [339]2 years ago
5 0

Answer:

1.2 units

Step-by-step explanation:

2.6(d + 1.4) - 2.3d = 4

2.6d + 3.64 - 2.3d = 4

0.3d + 3.64 = 4

0.3d = 0.36

d = 1.2

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Well, lets add 0.125 to 4.1.

We would get 4.225.

Finally we can check.

4.225-0.125= 4.1

How did we get it? What i did is I did the opposite. Instead of subtracting 0.125 I added it.

N= 4.225
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Ty is eight inches shorter than his brother Reece. If Ty is 42 inches tall, how tall is Reece.
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Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32)
Black_prince [1.1K]

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The  temperature in at which a certain chemical reaction takes place.

                             Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

                             P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

                             P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

                             P ( 1.8*X + 32 ≤ 1.8*η + 32 )

                             P ( 1.8*X ≤ 1.8*η )   ..... Cancel "1.8" on both sides.

                            P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

b)

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

                             P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

          P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

                                                 = P ( 1.8*X ≤ 1.8*p_0.9 )

                                                 = P ( X  ≤ p_0.9 )

                                                 = 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

c)

- The more general relation between two random variate "Y" and "X" is given:

                            Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

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                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

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- When a is negative,

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                                                 = P ( X  ≥ p_% )

                                                 = 1 - np_%        

                                                           

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