Distribute
(7x)(4x^2-3x-6)+(-3)(4x^2-3x-6)=
28x^3-21x^2-42x-12x^2+9x+18=
28x^3-21x^2-12x^2-42x+9x+18=
28x^3-33x^2-33x+18
D is the correct answer
Answer: x = -5/2 and x = -3/2
Step-by-step explanation:
(2x + 5)2 = 4x (x + 5) +25
4x + 10 = 4x² + 20x + 25
[minus 4x on both sides.]
10 = 4x² + 16x + 25
[minus 10 on both sides.]
0 = 4x² + 16x + 15
ac = 4(15) = 60,then find the factors that add up to 16, which is 6 and 10.
0 = 4x² + 6x + 10x + 15
0 = 2x(2x + 3) + 5(2x + 3)
0 = (2x + 5)(2x + 3)
2x + 5 = 0 2x + 3 = 0
2x = -5 2x = -3
x = -5/2 x = -3/2
1/2x + 1 = 2/3x
1/2x - 2/3x = -1
-x/6 = -1
x = 6
Hope this helps!
