A rectangular swimming pool is to be filled with water. The pool has a uniform depth of 3 meters and

What are the coordinates of M' after triangle MNO is reflected over the y-axis, and rotated 90 degrees clockwise with

exis [7]

(0,-6) because it is reflected and rotated

3 0

3 years ago

Read 2 more answers

The cylinder is 20cm high and radius of its circular face is 3cm What is the total perimeter and area of the whole net?

trasher [3.6K]

Answer: $52\ cm,\ 176.55\ cm^2$

Step-by-step explanation:

Given

The cylinder is 20 cm high

The radius of the cylinder is $r=3\ cm$

The total area of the figure is the sum of the rectangle and two circles

$\Rightarrow \text{Perimeter P=}2[h+2r]\\\Rightarrow P=2[20+6]\\\Rightarrow P=52\ cm$

The total area of the figure is

$\Rightarrow \text{Area A=}h\times 2r+2\pi r^2\\\Rightarrow A=20\times 6+2\times \pi \times 3^2\\\Rightarrow A=120+18\pi\\\Rightarrow A=176.55\ cm^2$

3 0

2 years ago

This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.

jolli1 [7]

Answer:

a) $y(t) = \sqrt{2t + 1 }$

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

$\frac{dy}{dt} = \frac{1}{y} \\ \\ ydy = dt \\ \\ integrating \: both \: sides \\ \\ \int y \: dy = \int 1 \: dt \\ \\ \frac{ {y}^{2} }{2} = t + c \\ \\ {y}^{2} = 2t + 2c \\ \\ y (t)= \sqrt{2t + 2c} ...(1) \\ \\ a) \: \: \: plug \: t = 0 \: in \: (1) \\ \\ y (0)= \sqrt{2(0) +2 c} \\ \\ y (0)= \sqrt{0 +2 c} \\ \\ 1 = \sqrt{2c} \: \: ( \because \: y (0)=1) \\ \\ 2c = 1 \: \implies \: c = \frac{1}{2} \\ \\ plug \: c = \frac{1}{2} \: in \: (1) \\ \\ y(t) = \sqrt{2t + 2 \times \frac{1}{2} } \\ \\ \huge \: \red {y(t) = \sqrt{2t + 1 } } \\ \\b) \: \: plug \: y(t) = 2 \: in \: above \: equation \\ \\ 2 = \sqrt{2t + 1} \\ \\ 4 = 2t + 1 \: \\ (squaring \: both \: sides) \\ \\ 4 - 1 = 2t \\ \\ 2t = 3 \\ \\ t = \frac{3}{2} \\ \\ t = 1.5 \: hours \\$