18/20=K/110
20K= 110*18
20K= 1980
K= 99
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
Answer:
1. (n + 3)(5n + 8)
2. (x - 4)(7x - 4)
3. (k + 8)(7k + 1)
Step-by-step explanation:
1. We have to factorize 5n² + 23n + 24.
Now, 5n² + 23n + 24
= 5n² + 15n + 8n + 24
= 5n (n + 3) + 8 (n + 3)
=(n + 3)(5n + 8) (Answer)
2. We have to factorize 7x² - 32x + 16
Now, 7x² - 32x + 16
= 7x² - 28x - 4x + 16
= 7x (x - 4) - 4 (x - 4)
= (x - 4)(7x - 4) (Answer)
3. We have to factorize 7k² + 57k + 8
Now, 7k² + 57k + 8
= 7k² + 56k + k + 8
= 7k (k + 8) + 1 (k + 8)
= (k + 8)(7k + 1) (Answer)
Answer:
8 in
Step-by-step explanation:
In a cube, the length, width, and height are all the same.
10(4x-1) is the answer to your question my friend