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3 years ago

I dont understand this, can i get some help please

Mathematics

1 answer:

Ray Of Light [21]3 years ago

3 0

When we want to find the roots of a one-variable function, we look for where its graph intersects the x-axis. In this case, the graph intersects the x-axis at $x=1.$

The vertex of a parabola is the highest or lowest point on it, depending on whether the leading coefficient of the quadratic function is negative or positive. In this case, we see that the lowest point is $(1,0).$

For the y-intercept, just look for where the graph intersects the y-axis; in this case, that point is $(0,1).$

Using this information, the vertex-form equation of the parabola is $y=1\cdot(x-1)^2+0,$ so the factors are two copies of $x-1.$ In this case, the value of $a$ in the equation $y=a(x-h)^2+k$ was conveniently 1; if that's not the case, you'll want to plug in $x=0$ to solve for the value of a that gives the correct y-intercept.

Does that help clear things up?

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Tatiana [17]

A, C, D, F? Not sure but took a good guess

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3 years ago

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Cable has 24 pennies he has hafe as many nickels as pennies he has 5 more dimes than nickels he has 6 fewer quarters than dimes

Andreyy89

Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6

Therefore...

Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11

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3 years ago

What is 12-2x6 + 2/2 ?

garri49 [273]

$12-2*6 + \frac{2}{2}= \\
12-12+1 = 0 + 1 = 1$

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3 years ago

Drag values to complete each equation.

Alex777 [14]

Answer:

1. A. 1

2. D. $17^9$

Step-by-step explanation:

Properties used:

Power of a Power Property
Product Property
Quotient Property
Zero Exponent Property

1. First, let's deal with the numerator.

$(17^3)^6$ can be turned into $17^1^8$ by using the Power of a Power Property.

And then use the Product Property, $(17^1^8)(17^-^1^0) = 17^8$

So now, our fraction is this: $\frac{17^8}{17^8}$

All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property: $\frac{a^m}{a^n} = a^m^-^n$ or $\frac{1}{a^(^n^-^m^)}$ . Which then you plug the numbers in: $\frac{17^8}{17^8} = 17^8^-^8 = 17^0$ . And since we know that in Zero Exponent Property: $a^0 = 1$ , we can see that $17^0 = 1$ . So either way, we get 1.