Question

Find the equation of a line parallel to x=−5 that contains the point (3,−2)

Answer 1

Answer:

4y+x = -4

Step-by-step explanation:

For the line x = -5, this is an x intercept written as (-5, 0)

Next is to find the equation of a line passing through (-5,0) and (3, -2)

Slope m = -2-0/3-(-5)

m = -2/8

m = -1/4

Get the y intercept

Substitute m =-1/4 and (-5,0) into the expression y - mx+c

0 = -1/4(-5) + c

0 = 5/4 + c

c = -5/4

Get the required equation;

y = -1/4 x - 5/4

4y = -x - 4

4y+x = -4

This gives the required equation