Hiroto's texting plan costs $20 per month, plus $0.05 per
2 answers:
The question is incomplete:
Hiroto's texting plan costs $20 per month, plus $0.05 per text message that is sent or received. Emilia's plan costs $10 per month and $0.25 per text. Using the graph below, which statement is true?
A. Hiroto’s plan costs more than Emilia’s plan when more than 50 texts are sent.
B. Both plans cost the same when 22 texts are sent.
C. Emilia’s plan costs more than Hiroto’s plan when more than 22 texts are sent.
D. Both plans cost the same when 50 texts are sent.
THE GRAPH IS ATTACHED.
Answer:
D. Both plans cost the same when 50 texts are sent.
Explanation:
The answer is that both plans cost the same when 50 texts are sent as both lines intersect in 50 texts with a price of $22.5 which means that they cost the same.
The other options are not right:
-Hiroto’s plan costs more than Emilia’s plan when more than 50 texts are sent. This is not true because in the graph you can see that after 50 texts Emilia's line is higher which indicates that her plan has a higher costs.
-Both plans cost the same when 22 texts are sent. This is not true because the lines don't intersect at the same point when 22 texts are sent.
-Emilia’s plan costs more than Hiroto’s plan when more than 22 texts are sent. This is false because when 22 texts are sent Emilia's plan costs around $15.5 and Hiroto's plan costs around $21 and Hiroto's plan is more expensive until they reach 50 texts that is the only point where they cost the same.
You might be interested in
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
Hence, c = 6 and d = 2