<span>Tammy rents an apartment close to her school campus. The equation that is given is this one:
r = 355m,
where r is the amount spend on the rent.
m is the number of months.
In order to get the constant proportionality of r to m in this relationship, then we can set a constant k variable.
r = 355 m (k)
k = 1 r / 355 m
1 hour spent, it takes you to spend 355.</span>
The value of the function at x = 5, will be 343. Then the correct option is A.
<h3>What is an arithmetic sequence?</h3>
Let a₁ be the first term and r be the common ratio.
Then the nth term of the geometric sequence is given as,
aₙ = a₁ · (r)ⁿ⁻¹
We know that the first term is 1/7 and the common ratio is 7.
Then the equation will be
Then the value of the function at x = 5, will be
y = (1/7) · (7)⁵⁻¹
y = (1/7) · (7)⁴
y = 7³
y = 343
Thus, the value of the function at x = 5, will be 343.
Then the correct option is A.
More about the arithmetic sequence link is given below.
brainly.com/question/12373434
#SPJ1
The answer is expressions D, E, and G.
In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.
Options A and B only have 1 term, an x or y³, so these are incorrect.
Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.
D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.
G has 3 unique terms, x³, x^4, and 7x, so this is correct.
When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.
I hope this helps!
Answer:
is a subset of 
Step-by-step explanation:
Required
Difference between subset and proper subset
To answer this question, I will use the following illustration.
In the above sets, set B is a proper subset of set A because all elements of B can be found in A, but not element of A can be found in B.
Set C is a subset of A because 
Using the above illustration, we have:
and
is a subset of , because 5 and 8 are in but 2 which ca be found in is not in
Answer:
R-{-5}
Step-by-step explanation:
you get the vertex by making the denominator =0
ex.z+5=0 ,z=-5
then we see if the rational function has a constant beside it ex. 3÷z+5-3 ,but in this you Don't have one so its 0
so the vertex would be (-5,0)
the domain =R-{-5} , range=R-{0}
