All categories

3 years ago

30 POINTS!!!

Mathematics

2 answers:

Sedaia [141]3 years ago

6 0

Answer:

250 feet

Step-by-step explanation:

Vertex: (250,300)

Minimum height is 300 when the horizontal distance is 250

Elza [17]3 years ago

3 0

Step-by-step explanation:

<u>Step 1: Find the smallest height</u>

If you look at the graph, you can tell that at 250 feet, the height in feet is the lowest and it is at 250. Therefore, the vertex is also (250, 250). But, we are just looking for the x-value which will be 250.

Answer: Option A, 250 feet... you were correct :) Good Job

You might be interested in

Prove that 7 + 3 root 2 is not a rational number

Tanya [424]

Answer:

Step-by-step explanation:

let 7 + 3√2 be an rational number where

7+3√2 = a/b [ a and b are coprime and b is not equal to zero]

3√2= a/b-7

3√2 =( a-7b) /b

√2 = (a-7b) /3b .....(i)

Now ,from equation (i) ,we get that √2 is rational but we know that √2 is irrational. so actually 7 + 3√2 is irrational not rational. thus our assumption is wrong. The number is irrational.

5 0

4 years ago

Read 2 more answers

Which equation can be used to find the measure of Arc E H G?

anygoal [31]

Answer:

I need more context ,like the graph to figure this out.

Step-by-step explanation:

5 0

3 years ago

Which of the following ordered pairs represents the solution to the system given below?

pentagon [3]

(3,-1) just fill it in and the only one that makes sense is the first one

4 0

3 years ago

Passes through (-4, -5), slope = 3/4

ra1l [238]

Answer:

Step-by-step explanation:

y+5 = ¾(x+4)

4 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

8 0

3 years ago