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Amanda [17]
3 years ago
11

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

PLEASE HELP ME ASAP!!!

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

The area of the entire yellow region is 48 cm^2.

Step-by-step explanation:

See the attached image :)

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The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

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4 years ago
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3 years ago
The second term of a geometric progression is -576 and the fifth term is 243. Find:
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The answor is C because the sun the infinity is infatuated
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3 years ago
Find the average value of the following numbers 87, 79, 84, 70, 90
dem82 [27]

82

Explanation

the average is calculated by dividing the sum of the values in the set by their number.

Step 1

Let

\begin{gathered} \text{set}=\lbrace87,79,84,70,90\rbrace \\ the\text{ sum of the values is=87+79+84+70+90}=410 \\ n\text{umber of values= 5} \end{gathered}

Step 2

apply the equation

\text{Average}=\text{ }\frac{the\text{ sum of the values}}{\nu mber\text{ of values}}=\frac{410}{5}=82

so, the answer is 82

6 0
1 year ago
A tennis ball is in a cylindrical container. The ball has a radius of 5 inches and the cylinder has a height of 8 inches. How mu
Nostrana [21]

Answer:

104.7 in^3

Step-by-step explanation:

Step one:

given data

The ball has a radius of 5 inches and

the cylinder has a height of 8 inches

Step two:

The volume of the cylinder

v= \pi r^2 h

substitute our data

v= 3.142*5^2*8\\\\v=628.4in^3

The volume of the ball

v=4/3 \pi r^3

substitute our data

v= 4/3 *3.142*5^3\\\\v= 523.7 in^3

The space will have a volume of

=628.4-523.7

=104.7 in^3

7 0
3 years ago
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