Answer:
The probability of the chosen ball being shiny conditional on it being red is; 0.375
Step-by-step explanation:
Let A be the event that a red ball has been chosen
Let B be the event that a shiny ball has been chosen
Let S be the total outcomes = 150 balls
Thus;
P(A ∩ B ) = 36/150
A ∩ B' = 150 - 36 - 54
A ∩ B' = 60
Thus; P(A ∩ B') = 60/150
P(A') = 54/150
P(A) = (150 - 54)/150 = 96/150
Thus, probability of the chosen ball being shiny conditional on it being red is;
P(B | A) = P(B ∩ A)/P(A)
Thus; P(B | A) = (36/150)/(96/150)
P(B | A) = 0.375
Answer:
Answer to fourth part is :
Angle ABC= Angle DBC
So for fifth part reason answer is ASA congruency.
Step-by-step explanation:
Here we are given that CB bisects angle ABD and angle ACD.
So we have ,
Angle ABC= Angle DBC
Answer to fourth part is :
Angle ABC= Angle DBC
Now here we have two angles and one side equal in two triangles.
So we can say that ASA congruency fits in the best here.
So for fifth part reason answer is ASA congruency.
I think it's along the y-axis.....
The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2<span> + </span><span>k, (h, k) is the vertex of the equation.</span>
Area abc def cuase its 126-72+28=82 so abc def
