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Elena-2011 [213]

3 years ago

11

Three boxes of cereal weigh 379.4 grams,424.25 grams,and 379.37 grams. What is the difference between the lightest and the heavi

est box?

1 answer:

TiliK225 [7]3 years ago

8 0

Answer:

44.88

Step-by-step explanation:

Heaviest box = 424.25

Lightest box = 379.37

424.25 - 379.37 = 44.88

Hope this helps!

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46 degrees (4x) degrees

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Answer:

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Ben is the youngest of four children. Bob is 5 years older than Ben, Bridget is twice as old as Bob, and Brian is 3 years younge

zhannawk [14.2K]

Answer:

bob is 7 Brian is 11 and bridget is 14

Step-by-step explanation:

if ben is 2 and bob is 5 years older then him he would be 7 if Brian is 3 years younger then bridget he would be 11 and if bridget is 2 times older than bob she would be 14.

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Angle of a triangle measures 115° the other two angles are in the ratio of 4:9 what are the measures of those two angles

nasty-shy [4]

Answer:

20, 45

Step-by-step explanation:

A triangle has 180 degrees interior angle measure. One angle measure 115 so that means the other two angles must add up to 65.

The remaning angles form a ratio of 4:9. This means we must split 65 into a ratio of. 4:9

A ratio partition parts of something. We can add the ratio intergers to find it full length.

4+9=13.

Divide 65/13=5.

Multiply 5x4 and 5x9 serpately.

We get 20 and 45

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3 years ago

Help ASAP!!!!<br> Which statement about the graph of the function y=(1/3)x are true?

mafiozo [28]

Answer:

Step-by-step explanation:

1) False: The function is decreasing (because the base, 1/3, is between 0 and 1).

2) True: The function is decreasing (see #1, above)

3) False: There is no x-intercept.

4) True: If x is 0, then y = (1/3)^0 = 1.

5) False: the range consists of the set of all real numbers greater than zero.

7 0

3 years ago

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Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

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3 years ago

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