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Lostsunrise [7]

2 years ago

12

. Write a number in which the value of the 6 is one tenth the value of the 6 ir 35,629.

1 answer:

Semenov [28]2 years ago

4 0

Answer:

65

Step-by-step explanation:

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Round the fraction 7 4/5 to the nearest whole number

Over [174]

Im not sure if you are saying 74/5 or 7 and 4 fifths but in the case you'r saying 74/5 you would first round to see the highest number that 5 can go to without being a decimal. Which would be 70 so you would count how many times 5 can go into 70, which would be 14, so the left over is 4/5 so you would check to see if it can be simplified which it can't so the final answer is 14 and 4/5

3 0

3 years ago

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Is 19/72 greater than 1/4

alina1380 [7]

Answer:

Yes

Step-by-step explanation:

$\frac{1}{4} = \frac{1 \times 18}{4 \times 18} = \frac{18}{72} \\ \because \: 19 > 18 \\ \therefore \: \frac{19}{72} > \frac{1}{4} \\$

7 0

3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

kvasek [131]

Answer:

1. The total number of students in the 25-34 age group

2. 2124/19558*100= 10.9 %

3 0

3 years ago

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You want to buy an item that costs $100. Which is the most cost-effective choice for buying the item?

Lilit [14]

C. Buying it a percent discount without sales tax.

Because of not having to pay $10, so it is awesome.

5 0

3 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It

Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 450 gram

Sample mean, $\bar{x}$ = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

$\sigma^2 = 256\\\sigma = \sqrt{256} = 16$

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25$

Now,

Degree of freedom =

$=n-1 = 16-1=15$

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .

5 0

3 years ago