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otez555 [7]
3 years ago
10

The sum of x and it’s opposite is always zero?

Mathematics
1 answer:
jeka943 years ago
5 0

Answer:

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

Step-by-step explanation:

For this case we can verify if the following expression is true or false:

The sum of x and it’s opposite is always zero?

If we want to proof this we need to show that for any number is true.

1) Let's consider the first case with the number 0 the oppose is also 0 and we have that 0-0=0 so then applies

2) Now let's consider any real number a no matter positive or negative we will have that:

a-a =0

Or in the other case:

-a -(-a) =-a +a=0

So then we can conclude that the expression is a general rule and is true

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ANSWER ASAP PLZZ three times William's age, w, is less than his cousin Sandra's age, 15. On the number line below, select from t
Eva8 [605]

Answer:

w = 13, 11, 12

Step-by-step explanation:

3 (15 - w)

3 (15 - 13)

3 (2)

w = 6

___

3 (15 - x)

3 (15 - 11)

3 (4)

w = 12

___

3 (15 - x)

3 (15 - 12)

3 (3)

w = 9

(hope this helps!)

8 0
2 years ago
Given f(x) = x3 – 2x2 – x + 2, <br><br> the roots of f(x)
anyanavicka [17]

f(x) = x³ – 2x² – x + 2

 

 0 = x3 – 2x2 – x + 2

 (x-2)(x-1)(x+1)=0

 x1=-1

 x2=1

 x3=2

5 0
2 years ago
Read 2 more answers
I need help asap someone please help ​
Dvinal [7]

Answer:

c = 20

so , c >20 ...........

8 0
3 years ago
Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced
Butoxors [25]

Answer:

1) \chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

2) df = c-1 = 2-1

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

And if we replace we got:

\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

Part 2

For this case the degreed of freedom are given by:

df = c-1 = 2-1

Where c represent the number of categories c=2

And we can calculate the p value given by:

p_v = P(\chi^2_{1} >2)=0.157

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0
3 years ago
Andy is designing a dice tray in the shape of a rectangular prism to use during a role-playing game. The tray needs to be three
aliya0001 [1]
<span>The volume of a rectangular prism is 
 V = l · w · h
V= 252 cm3
h= 3 cm
l=5+W
W=x then l=5+x
V=(5+x)*x*3=252
3x</span><span>^2+15x=252 cm3

</span><span>the equation that models the volume of the tray in terms of its width, x, in centimeters.
</span>3x^2 +15x=252 cm3<span>
</span>

for width=7.5 cm

3x^2 +15x=3*(7.5) ^2+15*7.5= 281.25 cm3

<span>281.25>252 </span><span> </span>

<span>it is not possible that the width is 7.5 cms</span>


4 0
3 years ago
Read 2 more answers
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