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Andre45 [30]
3 years ago
7

Suppose economists observe that an increase in government spending of $15 billion raises the total demand for goods and services

by $60 billion.
If these economists ignore the possibility of crowding out, they would estimate the marginal propensity to consume (MPC) to be

1/4

3/4

1/4

4

Now suppose the economists allow for crowding out.Their new estimate of the MPC would be larger or smaller than their initial one
Business
1 answer:
kozerog [31]3 years ago
8 0

Answer:

1/4

Explanation:

MPC = dC/dY

dC is the change in consumption

dY is the change in demand for goods and services.

MPC = 15/60 = 1/4

If allowance is made for crowding out, the new estimate will be larger.

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Landor Appliance Corporation makes and sells electric fans. Each fan regularly sells for $40. The following cost data per fan is
olga55 [171]

Answer:$50

Explanation:

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3 years ago
Firms that charge relatively low prices and offer substantial differentiation are following a best-cost strategy. A best cost st
satela [25.4K]

Answer: The answer is given below

Explanation:

A best-cost strategy is a strategy that is used by companies as they focus on low cost in order to give their customers better value for the money spent on the purchase of goods or services from them. The goal of this strategy is to keep the prices and costs lower when compared with the other competitors that offer similar products.

This strategy can be very successful in retail stores. Retail stores offer similar products to their competitors and using this strategy could help in making the store get more customers and hence push up its income.

For this strategy to work in such industry, firstly, the company will need to study its market very well, get to know its competitors, have a good working relationship with the manufacturers of different products, and have a friendly and amazing staffs who know what is and expected of them. With all these in place, success will be achievable.

An example of a firm in Jacksonville that is following a best cost strategy is

McDonald. The company over the years, has been successful and laid s foundation of offering fast-food meals that are of low prices and affordable.

4 0
3 years ago
Phil, age 20, is single and can be claimed as a dependent on his parent's return. He had $150 in interest income and wages of $7
Korvikt [17]

Answer: B - $7,150

Explanation: Standard taxation is an option by IRS to reduce an inidvidual taxable income. this is subject to an individuals filling status.

Phil who is aged 20, single and who can claim a dependent on his parents tax filling return. As of 2019, his standard tax deduction is limited to his earned income plus $350.

According to the above question, Phil earns $7,000 as wages plus $150 in interest income.

From the above information, Phil has a standard tax of $7,150.

3 0
3 years ago
A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius
anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

T^2 \alpha  a^3

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 \times 10^8 \ km

Therefore, T^2 = ca^3

c= \dfrac{365^2}{(1.496 \times 10^8)^3}

c = 3.9791 \times 10^{20} \ day^2/km^3

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

T^2 = ca^3

a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}

a^3 = 2.9092 \times 10^{27}

a= \sqrt[3]{2.9092 \times 10^{27}}

a = 1.4275 \times 10^9 \ km

However, the velocity for a perihelion = 10.18 km/s

Using the formula

v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})} to calculate the radius, we have:

G = 6.674 \times 10^{-11}

M = 1.989\times 10^{30} \ kg

r = perihelion

v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})

(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30}  ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})

7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}

\dfrac{2}{r} = 1.4824 \times 10^{-12}

r = \dfrac{2}{1.4824 \times 10^{-12}}

r = 1.349 \times 10^{12}

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)

1.349 \times 10^{12}  -  1.425 \times 10^{12}= -  1.425 \times 10^{12} (e)

-7.6\times 10^{10}= -  1.425 \times 10^{12} (e)

\dfrac{-7.6\times 10^{10}}{-  1.425 \times 10^{12}}=  (e)

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

r = 1.425 \times 10^{12} ( 1 + 0.0533)

r = 1.50 \times 10^{12} \ m

to nautical miles, we have:

r = 1.50 \times 10^{12} \times 0.00054  \ nautical \ mile

radius of aphelion \mathbf{r = 8.10 \times 10^8} nautical miles

In respect to the value of a( i.e 1.4275 \times  10^9 \ km)

the body of the solar system is Saturn

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OverLord2011 [107]
customers are always right
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