All categories

3 years ago

What’s the area of this triangle?

Mathematics

2 answers:

dsp733 years ago

7 0

The answer is 21
Here’s my work:

STALIN [3.7K]3 years ago

5 0

Area = 1/2 x base x height.

Base is 6 units long, height is 7 units long.

Area = 1/2 x 6 x 7 = 21 square units.

You might be interested in

Is 27/107 irrational

VladimirAG [237]

No 27/107 is not irrational because both numbers can be simplified to be a smaller fraction/number.

8 0

3 years ago

2. Write an equation in siope-interceptform to represente relationship in the table

iren2701 [21]

Answer:

-4/-5

Step-by-step explanation:

you have to pick 2 numbers from the y row and the x row i picked -7 and 3 and -5 and 0 so first you would do 3-(-7) and that would be -4 and then do -5-0 and that would be -5 then you would put the y/x

4 0

3 years ago

If DE = 7x + 3 and EF = 9x - 19,<br> then EF = ?

ANEK [815]

Answer:

Step-by-step explanation:

7x + 3 = 9x - 19

-2x + 3 = -19

-2x = -22

x = 11

DE= 7(11) + 3 = 77 + 3 = 80

EF = 9(11) - 19 = 99 - 19 = 80

80 + 80 = 160 for DF

6 0

4 years ago

There are only two more stranded aliens. See if you can pick them up in a single trip. Then answer the question.

ad-work [718]

Answer: I got you.....the correct answer will be (-2,-3) aka D

Step-by-step explanation:

7 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

8 0

4 years ago