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Dmitriy789 [7]
3 years ago
6

Find the volume of the Canada post mailbox shown below.

Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer:

1,152,112.5 cm3

Step-by-step explanation:

To find the volume of this mailbox we can separate in two parts:

A rectangular prism, with dimensions 180 cm x 70 cm x 85.5 cm and

A triangular prism, with dimensions 25 cm x 70 cm x 85.5 cm.

Now we need to find the volume of both parts:

V_rectangular = 180 * 70 * 85.5 = 1,077,300 cm3

V_triangular = (1/2) * 25 * 70 * 85.5 = 74,812.5 cm3

Finally, we just need to sum the volumes of the parts:

V_mailbox = V_rectangular + V_triangular = 1077300 + 74812.5 = 1,152,112.5 cm3

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The perimeter of a rectangle is (10x2).if it's width is (2x-1),which expression represents the length
alexandr402 [8]

Answer: b. 3x + 2

Step-by-step explanation:

2l + 2w = p

2l + 2(2x - 1) = 10x + 2

2l + 4x - 2 = 10x + 2

2l = 6x + 4

l = 3x + 2

4 0
3 years ago
Find the measures of the angles of a triangle of the measure of one angle is three times the measure of a second angle and the t
Vinil7 [7]

Answer:

hii

x=30

Step-by-step explanation:

x+3x+5x-90=180

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5 0
3 years ago
Which table represents the graph of a logarithmic function in the form y=log3x when b>1?
alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u>y = log_{b} (x)<u><em></em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function y = log_{b} (x)   if b >1

Given first table

i)

put x = \frac{1}{8}     given b > 1 so we can choose b = 2

y = log_{2} (\frac{1}{8} )

y = log_{2} (2^{-3}  )

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-3}  ) = -3 log_{2} (2) = -3 (1) = -3

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em>\frac{1}{4}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{4} )<em></em>

<em></em>y = log_{2} (2^{-2}  )<em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

y = log_{2} (2^{-2}  ) = -2 log_{2} (2) = -2 (1) = -2

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em>\frac{1}{2}<em>     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (\frac{1}{2} )<em></em>

y = log_{2} (2^{-1}  )

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

y = log_{2} (2^{-1}  ) = -1 log_{2} (2) = - (1) = -1

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1     given b > 1 so we can choose b = 2</em>

<em></em>y = log_{2} (1 )<em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em>2<em>     given b > 1 so we can choose b = 2</em>

y = log_{2} (2 )

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x                    1/8            1/4             1/2              1             2</em>

<em>y                    -3                 -2            -1               0               1</em>

<em></em>

8 0
3 years ago
Read 2 more answers
9) p(a) = a) – 3a; Find p(-2)<br> A) 18<br> B) 198<br> C) -110<br> D) -2
Afina-wow [57]
ANSWER: B)198



Have a great day!
6 0
2 years ago
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