Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
A. (-1, 3)
Step-by-step explanation:
To solve, find which point in the options are in the double shaded region (the region that is shaded the darkest which is the region above the point where the lines cross).
A. (-1, 3) is the correct answer because it falls in the correct region.
B. (-4, 1) is not the correct answer because it does not fall ABOVE both lines like the question says.
C. (0, 1) is not the correct answer because it falls in the 2nd darkest region.
Answer: -x^2 + 15x
Step-by-step explanation:
Answer:
81.6
Step-by-step explanation:
mean/average of her grade = sum of all scores/the number of scores
= (93+82+74+92+67)/5
= 81.6
Answer:
14000
Explaination:
spwithvat = sp without vat + 13% of sp without vat
let, sp without vat be x.
sp with vat= x + 13% of x.
or, 13447 = x + 13/100 × x
or, 1344700 = 113x
or, x= 1344700/113
x = 11900
Let, mp be y.
sp with vat = mp - 15% of mp
or, 11900 = y - 15/100 × y
or, 1190000 = 85y
or, y= 1190000/85
y= 14000
