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cestrela7 [59]
2 years ago
8

Help now plssss!!!!!

Mathematics
1 answer:
blondinia [14]2 years ago
7 0

Answer:

common denominator = 24

1/8 = 3/24

1/6 = 4/24

Step-by-step explanation:

to find common denominator:

8 - 8, 16, 24

6 - 6, 12, 18, 24

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If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
The set of ordered pairs represents a function. Write a rule that represents the function.
maks197457 [2]
Y=3x^3 is the awnser
5 0
3 years ago
What is the value of a?<br> a-2 = 3462
Brums [2.3K]

Step-by-step explanation:

a-2=3+6a/3

By cross multiply

3(a-2)=3+6a

3a-6=3+6a

-6-3=6a-3a

-9=3a

a=-3

8 0
3 years ago
Which equation correctly shows how to determine the distance between the points (9,-2) and (6.3) on a coordinate grid?
Nastasia [14]

Answer:

d = \sqrt{(6 - 9)^{2}+ (3 - (-2))^{2} }

Step-by-step explanation:

The distance formula is d= \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}     }.

6 is x_{2}, 9 is x_{1}, 3 is y_{2}, and -2 is y_{1}.

When you plug these into the formula, you get d = \sqrt{(6 - 9)^{2}+ (3 - (-2))^{2} }

7 0
3 years ago
Please help!! I need help with 1-6
jekas [21]

Answer:

sorry don't know

Step-by-step explanation:

7 0
2 years ago
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