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antiseptic1488 [7]
3 years ago
11

A box has a volume of 22 1/2 in³. Find the length of the box!

Mathematics
1 answer:
aliya0001 [1]3 years ago
3 0

Answer:

Length = 2.823 in (to 3 decimal places)  

Step-by-step explanation:

assuming that the box is a cubic box:

volume of box = 22\frac{1}{2} in³ = 22.5 in³

volume = Length × Length × Length = (Length)³

∴ (Length)³ = 22.5

∴ Length = ∛(22.5)

using the calculator punch ∛(22.5), and the answer is:

∴ Length = 2.823 in (to 3 decimal places)

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Applying the Procedure
Verizon [17]

Answer:

15 Square Inches

Step-by-step explanation:

Volume of the cone=40 cubic inches

Height of the cone=8 Inches

<u>Step 1:</u> Applying the formula for the volume of a cone

Volume of a Cone=\frac{1}{3}\pi r^2 h=\frac{1}{3} X $Base Area X Height

<u>Step 2:</u> Substituting values for the variables

40=\frac{1}{3} X $Base Area X 8

<u>Step 3:</u> Simplifying the right side

40=\frac{8}{3} X $Base Area

<u>Step 4:</u> Multiplying by the reciprocal

40X\frac{3}{8}=\frac{8}{3} X\frac{3}{8} X $Base Area\\

<u>Therefore, Base Area of the Cone=15 Square Inches</u>

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8 0
3 years ago
Find slope<br> I need help on this lol
irinina [24]

Step-by-step explanation:

slope =  \frac{4 - 0}{2 - 3}  \\ slope =  \frac{4}{ - 1}  \\ slope =  - 4

4 0
3 years ago
Please help i have a test and this is the only question im stuck on 30 points
tia_tia [17]
It’s D because the line is on the positive side of the graph. The y-intercept is positive 5 and x-intercept is positive 4, which makes a slope of 5/4.

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4 0
3 years ago
Greatest to least 73.05 74.01 73.50
marissa [1.9K]
Greatest to least:
74.01, 73.50, 73.05
7 0
3 years ago
Read 2 more answers
Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi
notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{68-74}{6}

z=\frac{-6}{6}=-1

Now let us find z-score for 86.

z=\frac{86-74}{6}    

z=\frac{12}{6}=2        

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,    

P(-1

P(2>Z)=.97725  

We will use formula P(a to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

P(-1

P(-1

Upon converting 0.81859 to percentage we will get

0.81859*100=81.859\approx 81.86

Therefore, 81.86% of final exam score will be between 68 and 86.  


3 0
3 years ago
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