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Orlov [11]
3 years ago
6

Rewrite each expression as a polynomial in standard form: x^2-5x+6 ÷ x-3 + x^3-1 ÷ x-1

Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

So in standard form equation will be x^2+2x-1

Step-by-step explanation:

We have given expression \frac{x^2-5x+6}{x-3}+\frac{x^3-1}{x-1}

Let first we solve first part of the expression

So \frac{x^2-5x+6}{x-3}=\frac{x^2-3x-2x+6}{x-3}=\frac{(x-3)(x-2)}{x-3}=x-2

Now second part \frac{x^3-1}{x-1}

We know the algebraic identity a^3-b^3=(a-b)(a^2+ab+b^2)

So by using this identity

\frac{x^3-1}{x-1}=\frac{(x-1)(x^2+x+1)}{x-1}=x^2+x+1

Now adding first and second part

x-2+x^2+x+1=x^2+2x-1

So in standard form equation will be x^2+2x-1

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