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Paul [167]
2 years ago
6

A cuboid has a base of 12. 5 cm by 20 cm. holds exactly 1 litre of water. What is the height.​

Mathematics
1 answer:
nikitadnepr [17]2 years ago
6 0

Answer:

4 cm

Step-by-step explanation:

V=L×W×H

V=1 litre = 1000 cm³

H= V/LW

1000/(12.5×20)=4

height= 4cm

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•°|NO LINKS PLEASE, LOOKING FOR REAL ANSWERS|°•
DedPeter [7]

Answer:

a2 + 2al (or) a2 + √a24+h2 a 2 4 + h 2

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What value of b makes the trinomial below a perfect square x^2-bx+100
Aloiza [94]
1. Perfect square trinomials, are 2nd degree polynomials, of the form          a x^{2} +bx+c so that a \neq 0, b \neq 0, c \neq 0, which can be written as perfect squares.

2. For example (x+1) ^{2} = x^{2} +2x+1
 
(3x-1)^{2}= (3x)^{2}-2(3x)+(-1) ^{2}= 9x^{2}-6x+1    


3. Thus x^{2} +2x+1, 9x^{2}-6x+1 are perfect square trinomials.

4. x^{2} -bx+100= x^{2} -bx+ 10^{2}= (x+10)^{2}   or  (x-10)^{2}

5. In the first case -b=20, so b=-20. In the second case, -b=-20, so b=20.

6. b∈{-20, 20}
6 0
2 years ago
Help please! i don't know what to do
Serhud [2]
I hope this helps you



9/9+18=x/x+10


9/27=x/x+10


1/3=x/x+10

3x=x+10

x=5


8 0
3 years ago
Elise ​says, "If you subtract 17 from my number and multiply the difference by negative 6​, the result is negative 126​." What i
Studentka2010 [4]
Well, I would just reverse it. It seems you just have to reverse the whole problem.
4 0
3 years ago
A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?
AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

Hence The width of the sandbox is 42\frac{2}{3} \ ft.

5 0
3 years ago
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