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3 years ago

HELLP What is the formula for finding the perimeter of a polygon?

Mathematics

2 answers:

Kaylis [27]3 years ago

8 0

Answer:

P=n*s

Step-by-step explanation:

n is the number of sides and s is the length of any one side.

Rzqust [24]3 years ago

8 0

Answer:

It depends on the polygon.

Perimeter is the distance around a figure, so the formula changes for what type of polygon it is. For example, a square would be 4l or the length of one side times 4.

To find the perimeter for any polygon, regular or irregular, use the distance formula for each side. Then add all values together.

The distance formula is $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Where $(x,y)$ is one edge and $(x_2 , y_2)$ is another edge, both belonging to the same side. This formula calculates the unit length of a side of your choice. For irregular figures, you have to use this formula for every side. For regular figures, just multiply the distance by how many sides there are.

Distance calculator for 2d grid: https://www.calculatorsoup.com/calculators/geometry-plane/distance-two-points.php

Distance formula explanation: https://www.khanacademy.org/math/geometry/hs-geo-analytic-geometry/hs-geo-distance-and-midpoints/v/distance-formula#:~:text=Learn%20how%20to%20find%20the,distance%20between%20any%20two%20points.

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I dont really understand this??

jeyben [28]

Answer:

$x\geq -53$

Step-by-step explanation:

The inequality includes -53.

The interval notation is $\:[-53,\:\infty \:)$

$\{ x \in \mathbb{R}: x \geq -53 \}$

8 0

3 years ago

Read 2 more answers

A particle moves according to a law of motion s = f(t), t ? 0, where t is measured in seconds and s in feet.

Usimov [2.4K]

Answer:

a) $\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

b) $v(t=3) = 3(3)^2 -18(3) +15=-12$

c) $t =1s, t=5s$

d) $[0,1) \cup (5,\infty)$

e) $D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

f) $a(t) = \frac{dv}{dt}= 6t -18$

g) The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

Step-by-step explanation:

For this case we have the following function given:

$f(t) = s = t^3 -9t^2 +15 t$

Part a: Find the velocity at time t.

For this case we just need to take the derivate of the position function respect to t like this:

$\frac{ds}{dt}= v(t) = 3t^2 -18t +15$

Part b: What is the velocity after 3 s?

For this case we just need to replace t=3 s into the velocity equation and we got:

$v(t=3) = 3(3)^2 -18(3) +15=-12$

Part c: When is the particle at rest?

The particle would be at rest when the velocity would be 0 so we need to solve the following equation:

$3t^2 -18 t +15 =0$

We can divide both sides of the equation by 3 and we got:

$t^2 -6t +5=0$

And if we factorize we need to find two numbers that added gives -6 and multiplied 5, so we got:

$(t-5)*(t-1) =0$

And for this case we got $t =1s, t=5s$

Part d: When is the particle moving in the positive direction? (Enter your answer in interval notation.)

For this case the particle is moving in the positive direction when the velocity is higher than 0:

$t^2 -6t +5 >0$

$(t-5) *(t-1)>0$

So then the intervals positive are $[0,1) \cup (5,\infty)$

Part e: Find the total distance traveled during the first 6 s.

We can calculate the total distance with the following integral:

$D= \int_{0}^1 3t^2 -18t +15 dt + |\int_{1}^5 3t^2 -18t +15 dt| +\int_{5}^6 3t^2 -18t +15 dt= t^3 -9t^2 +15 t \Big|_0^1 + t^3 -9t^2 +15 t \Big|_1^5 + t^3 -9t^2 +15 t \Big|_5^6$

And if we replace we got:

$D = [1 -9 +15] +[(5^3 -9* (5^2)+ 15*5)-(1-9+15)]+ [(6^3 -9(6)^2 +15*6)-(5^3 -9(5)^2 +15*5)] =7+ |32|+7 =46$

And we take the absolute value on the middle integral because the distance can't be negative.

Part f: Find the acceleration at time t.

For this case we ust need to take the derivate of the velocity respect to the time like this:

$a(t) = \frac{dv}{dt}= 6t -18$

Part g and h

The particle is speeding up $(1,3) \cup (5,\infty)$

And would be slowing down from $[0,1) \cup (3,5)$

5 0

3 years ago

If a = 1, find the values of b, c and d that make the given expression equivalent to the expression below.

vlada-n [284]

Answer:

To do this, you need to multiply out the expressions. This is a bit tedious, but remember like FOIL for binomials, for these trinomials you must multiply each term. If you need a step-by-step, I'd be happy to provide it. Let me know.

Once you have simplified the expression, you get

-x-9/2x-4

But, the problem stipulates that a must equal 1. We can equivalently factor out the negative sign and put it on the denominator with no change to write

x+9/-(2x-4) = x+9/-2x+4

So, seeing where each coefficient corresponds between the two expressions, you get a = 1, b = 9, c = –2, and d = 4.

8 0

3 years ago

Complete the ratio table explain or show your work (you must do either)

Ainat [17]

Answer:

7 21 35 49

3 9 18 27

Step-by-step explanation:

the top is going up by 14 and you subtract 9 from 27

4 0

3 years ago

Whats the equation of a line perpendicular to y= 0.25x-7 and passes through (-6,8)

-Dominant- [34]

$y - 8 = 4(x + 6)$
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.

8 0

3 years ago