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Sholpan [36]
3 years ago
14

Find an equation of the circle that has center (-1,1 ) and passes through (1,-6)

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

(x+1)^2+(y-1)^2=53

Step-by-step explanation:

The standard form for the equation of a circle is (x-h)^2+(y-k)^2=r^2, where h is the x coordinate of the center, k is the y coordinate, and r is the radius. To find the radius of this circle, we can simply find the distance from the center to any of the points on its circumference. Using the distance formula, you know that the distance from (-1,1) to (1,-6) is:

\sqrt{(1-(-1))^2+(1-(-6))^2}=\sqrt{2^2+7^2}=\sqrt{4+49}=\sqrt{53}

Therefore, the equation of this circle is:

(x+1)^2+(y-1)^2=53

Hope this helps!

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Answer:

9/10

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Since these fractions have different denominators, we need to find the least common multiple of the denominators.The least common multiple of 2 and 5 is 10, so we need to multiply to make each of the denominators = 10

1/2 ∗ 5/5 = 5/10

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Since these fractions have the same denominator, we can just add the numerators

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3 years ago
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Shalnov [3]

Answer:

See below.

Step-by-step explanation:

Formula:

a_n = 3(n + 4)

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Third term: n = 3

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Answer:

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I hope this helped and please mark me as brainliest!

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