(0.14×625×25)÷(2×12)
=91.15
91.15+625
=716.15
716.15÷24
=29.8
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
First get the length of the side the was cut (Hypotenuse).
We can use Pythagorean theorem: a^2+b^2 = c^2
a = 8, b = 3 = 1.5, c = ?
plug into forumla
8^2 + 3^2 = 73
a=8,
b=1.5,
c = sqrt( 73) or 8.5
Now add all sides together to get perimeter...
8+3+8.5 = 19.5
The perimeter of each sheet is 19.5in.
Answer:
.5299192646
Step-by-step explanation:
Just plug it in a calculator