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charle [14.2K]
3 years ago
14

What is the area of a circle with a radius of 1 foot? *Ht2 2*** seft 2 x ft?

Mathematics
1 answer:
Svetach [21]3 years ago
5 0

Answer:

pi

Step-by-step explanation:

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Step-by-step explanation: 3. 12240 watts

4. 101.82 pounds of insecticide.

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(7/3,4/3),(-1/3,2/3)
nevsk [136]
How is this a question?
5 0
3 years ago
Last week at a festival, a man sold 4 times as many tie-dyed T-shirts as silk screened shirts. He sold 180 shirts altogether. Ho
lyudmila [28]

Let the number of tie-dyed T-shirts = x

The man sold 4 times as many tie-dyed T-shirts as silk-screened shirts.

So, the number of silk-screened shirts = 4x

He sold 180 shirts altogether

So,

\begin{gathered} x+4x=180 \\ 5x=180 \\  \\ x=\frac{180}{5}=36 \end{gathered}

So, the number of tie-dyed shirts = 36

7 0
1 year ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
Determine whether it is a function or not. Give reason for your answer.
tekilochka [14]

Hey there!!

The given set is a function

( x , y ) - this is the form in which we write co-ordinates

In order to be a function , at least x values shall repeat.

Noted down all the x values

2 , -1, 4 , -2

None of the values is repeating.

Hence, the given data is a function

Hope my answer helps!

8 0
3 years ago
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